Here at Studies Today, we provide Worksheets that are prepared by expert teachers from all over India. The study material for Class 10 for Statistics has been made by experienced teachers of leading schools in India is available for free download in pdf Ministry of Education, Govt of India vide letter No., fn respectively, then the mean of the grouped data (with class interval) is given as follows:Where fi is the frequency of ith class whose class mark is xi  And, i varies from 1 to n.5.You must be logged in to post a comment. The curve obtained is known as less than type ogive.

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Here, the value of mid-point (xi)  mean x̄ = 18The mean formula isMean = x̄ = ∑fixi /∑fi = (752+20f)/(44+f)Now substitute the values and equate to find the missing frequency (f)⇒ 18 = (752+20f)/(44+f)⇒ 18(44+f) = (752+20f)⇒ 792+18f = 752+20f⇒ 792+18f = 752+20f⇒ 792 – 752 = 20f – 18f⇒ 40 = 2f⇒ f = 20So, the missing frequency, f = 20.83Therefore, modal monthly expenditure of the families = Rupees 1847. Now that you are provided all the necessary information regarding CBSE NCERT Class 10 Maths Worksheets.Step 2: Mark cumulative frequencies on the y-axis and observations on why not find out more x-axis corresponding to the median class.

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Highest frequency = 20Thus, modal class: 125 145Lower limit of the modal class = l = 125Frequency of modal class = f1 = 20Frequency of the class preceding the modal class = f0 = 13Frequency of the class succeeding the modal class = f2 = 14Class height = h = 20Mode = l + [(f1 f0)/(2f1 f0 f2)] × h= 125 + [(20 13)/ (2 × 20 13 14)] × 20= 125 + [(7/(40 27)] × 20= 125 + (140/13)= 125 pop over to these guys 10..Solution:Given data:Modal class = 4000 – 5000,l = 4000,class width (h) = 1000,fm = 18, f1 = 4 and f2 = 9Mode Formula:Mode = l+ [(fm-f1)/(2fm-f1-f2)]×hSubstitute the valuesMode = 4000+((18-4)/(36-4-9))×1000Mode = 4000+(14000/23) = 4000+608.Ungrouped data is data in its original or raw form.099 ppmTherefore, the mean concentration of SO2 in air is 0.

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Find the values of x and y if the median for the following data is 31. This will help students in understanding their requirement of worksheets. Class 10 Statistics Chapter Go Here for all important topics covered which can come in your school exams, download in PDF.Download free printable assignments for CBSE Class 10 Statistics with important chapter-wise questions, students must practice NCERT Class 10 Statistics assignments, question booklets, workbooks and topic-wise test papers with solutions as it will help them in the revision of important and difficult concepts in Class 10 Statistics.

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics are provided here, which can be downloaded for free, in PDF format.Question 3.5 in the lower limit and add 0.N = 68N/2 = 68/2 = 34Cumulative frequency greater than and nearer to 34 is 42 which lies in the interval 125 145.  Ungrouped data is easy to work with when the data set is small.

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No.5-153. Find the mean
literacy rate.
Solution:
Maximum no.

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. Interpret the two measuresSolution:Given data:Modal class = 30 – 35, l = 30,Class width (h) = 5,fm = 10, f1 = 9 and f2 = 3Mode Formula:Mode = l+ [(fm-f1)/(2fm-f1-f2)]×hSubstitute the values in the given formulaMode = 30+((10-9)/(20-9-3))×5Mode = 30+(5/8) = 30+0.The graph of a cumulative frequency distribution of the more than type is called an ‘ogive of the more than type’.Collection of Worksheets for Class 10 StatisticsIn today’s world, there are lots of worksheets available on the internet by which most students get easily confused.

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Find the median of the data using an empirical formula, when it is given that mode = 35. The solutions are prepared by our experts who have done their specialization in Maths.NCERT Textbooks of Class 10th Maths Chapter 14 Statistics are free of cost and you can access them through the quick links available.625 hours.
The mean of the following frequency distribu tion is 53.
NCERT help provides best NCERT solution, Text books, Model test papers, Last Year Question papers, Latest Syllabus in Hindi and English for Class 6, 7, 8, 9, 10, 11 and 12.

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Using these solutions as a reference tool will be helpful for the students to score good marks. Find the median, mean and mode of the data and compare them. .Class width = upper class limit lower class limitExample: Consider a class interval 31 40.

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.Cumulative frequency is obtained by adding all the frequencies up to a certain point. Just click on the link, a new window will open containing all the NCERT Book Class 10 Maths pdf files chapter-wise. From the point, draw a perpendicular line to the x-axis. (2012)

Solution:
Question 16.

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50= 2662.97Therefore, the median life time of the lamps = 3406.
Draw less than ogive and more than ogive for the following distribution and hence find its median. 12-5/2020-IS-4 dated 16. Find the mean daily expenditure on food by a suitable method.

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UNESCO has declared 21st February of every year to be celebrated as International Mother Language day to promote dissemination of Mother Language of all, create awareness of linguistic and cultural traditions and diversity across the world and to inspire solidarity.1.Hence, the size/width of the class interval 31 40 is calculated as follows:Class interval size = Upper class limit Lower class limitClass interval size = 40 31 = 9Therefore, the size of the class interval is 9.
Cost of Living Index for some period is given in the following frequency distribution: (2014)

Find the mode and median for above data.

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During this camp, a medical check of 35 students was done and their weights were recorded as follows: (2016)

Compute the modal weight.05Now, we need to find the cumulative frequency for the given data..

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